does python requests wait for response

Does Python Requests Wait for Response?

Python Requests is a popular library that is used for sending HTTP requests in Python. It is built on top of the urllib3 library and provides a simple and intuitive interface for making HTTP requests. One of the common questions that come up when using Python Requests is whether it waits for a response or not.

What is the Default Behavior of Python Requests?

By default, Python Requests waits for a response from the server. When you make a request using the requests library, it sends the request to the server and waits for a response. Once it receives the response, it returns it to the caller.

Here's an example:


import requests

response = requests.get('https://www.example.com')
print(response.text)

In this example, the requests.get() method sends a GET request to the URL specified and waits for a response. Once it receives the response, it prints the response text to the console.

Can You Change the Default Behavior?

Yes, you can change the default behavior of Python Requests by using the stream parameter. When you set stream=True, it tells Python Requests to not wait for the entire response to be downloaded before returning control to your code.

Here's an example:


import requests

response = requests.get('https://www.example.com', stream=True)

# Do something else while the response is being downloaded
for chunk in response.iter_content(chunk_size=1024):
    print(chunk)

In this example, we set stream=True to tell Python Requests to not wait for the entire response to be downloaded before returning control to our code. Instead, we use the iter_content() method to download the response in chunks of 1024 bytes. This allows us to do something else while the response is being downloaded.

Conclusion

In summary, Python Requests does wait for a response by default. However, you can change this behavior by using the stream parameter to tell Python Requests to not wait for the entire response to be downloaded before returning control to your code.