is python requests asynchronous

Is Python Requests Asynchronous?

Python Requests is a popular HTTP client library for Python. It simplifies sending HTTP requests and handling responses.

Overview of Asynchronous Operations

Asynchronous operations allow multiple tasks to run concurrently, without blocking each other. This can provide performance benefits in certain situations, such as when making multiple HTTP requests at the same time.

Python Requests and Asynchronous Operations

By default, Python Requests is not asynchronous. When you send a request with Requests, it will block until it receives a response.

However, there are ways to make Python Requests asynchronous. One way is to use a library like requests-futures, which uses threads to send requests asynchronously.

Another option is to use a different HTTP client library that supports asynchronous operations, such as aiohttp. This library uses the asyncio module to provide asynchronous functionality.

Example Code

Here is an example of using requests-futures to send HTTP requests asynchronously:

from concurrent.futures import ThreadPoolExecutor
from requests_futures.sessions import FuturesSession

session = FuturesSession(executor=ThreadPoolExecutor(max_workers=10))

urls = ['https://www.google.com', 'https://www.facebook.com', 'https://www.github.com']

futures = []
for url in urls:
    futures.append(session.get(url))

for future in futures:
    response = future.result()
    print(response.content)

And here is an example of using aiohttp to send HTTP requests asynchronously:

import aiohttp
import asyncio

async def request(url):
    async with aiohttp.ClientSession() as session:
        async with session.get(url) as response:
            return await response.text()

async def main():
    urls = ['https://www.google.com', 'https://www.facebook.com', 'https://www.github.com']
    tasks = []
    for url in urls:
        tasks.append(asyncio.ensure_future(request(url)))
    responses = await asyncio.gather(*tasks)
    for response in responses:
        print(response)

loop = asyncio.get_event_loop()
loop.run_until_complete(main())